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If the cos of angle x is eight seventeenths and the triangle was dilated to be two times as big as the original, what would be the value of the cos of x for the dilated triangle? Clue: Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no spaces.

Answer :

Answer:

8/17

Explanation:

The cos of angle x is eight seventeenth and the triangle was dilated to be two times as big as the original:

Cos x = 8/17

Let the original triangle be ∆ABC

Dilated triangle be ∆DEF

Find attached the diagram.

All sides of the triangle are scaled by the same factor when we apply a dilation.

DE = 2 × AB

EF = 2 × BC

DF = 2 × AC

∠A = ∠D

∠B = ∠E

∠C = ∠F

Dilation also known as scaling does not affect angle measure. The angle measures remain the same.

Therefore, The value of the cos of x for the dilated triangle = 8/17

${teks-lihat-gambar} Ike125

As the cos of angles is X which is 8/7th of the triangle which was dilated to be the 2 times as the original. The value cos X for the tringle would be  

  • Let the original triangle be ∆ABC  and the dilated would be ∆DEF.  All the sides of the triangles are scaled by the same factor when we apply a dilation.
  • DE = 2 × AB
  • EF = 2 × BC
  • DF = 2 × AC
  • ∠A = ∠D
  • ∠B = ∠E
  • ∠C = ∠F

 value of the cos in triangle = 8/17.

Learn more about the is eight seventeenths and the triangle.

brainly.com/question/9328997.